Question

Given(x+y)=13and xy=22, find the value of x^2+y^2.​

Answer 1

Answer:

Given,

x+y=13

xy =22

x²+y²=?

x²+y² can be written as ( x+y)²-2xy

so substitute given values

(x+y)²-2xy

=13²-2(22)

=169-44

=125

hence value of x²+y²=125

Answer 2

Step-by-step explanation:

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