Math, asked by as3217713, 5 months ago

Given (x - y) = 5 and xy = 36, find the value of x^2+ y^2​

Answers

Answered by mayankbhargava808
3

To find :-

Values of x and y

Solution :-

From equation 2, We get.

y = 36/x

Putting this value in equation 1 we get....

x - (36/x)= 5 ..........(3)

Multiplying equation 3 by x and rearranging, we get

x² - 5x -36 = 0

Now

x² - 9x + 4x -36 = 0

x(x - 9) + 4 (x - 9)

(x - 9) (x + 4)

x = 9 , 4

Therefore , we got two values of x

hence

If X = 9

then y = 36/9 = 4

And if x = 4

y = 36/4 = 9

IF answer is correct pls follow and like

Answered by mdabdulbaseer6
1

Answer:

x^2 + y^2 = 97

Step-by-step explanation:

Given :

(x-y) = 5

xy = 36

x^2 + y^2 = ?

Answer :

(x-y)^2 = x^2 + y^2 - 2xy

(5)^2 = x^2 + y^2 - 2(36)

25 = x^2 + y^2 -72

72 + 25 = x^2 + y^2

97 = x^2 + y^2

Thus, x^2 + y^2 = 97

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