Question

Given y=1/x+cos2x, find d^5y/dx^5

Answer 1

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Answer 2

Answer:

-5!/x^6 -32 sin 2x or -120.x^-6 - 32 sin 2x or -5!/x^6 + 32 cos (2x + 5π/2)
Any of this could be the answer

Step-by-step explanation:

Given: y = 1/x + cos 2x we have to find 5th derivative w.r.t x

We know y^n for 1/(ax + b) is (-1)^n . n! . a^n/ (ax + b)^ n+1
∴ y^n for 1/x will be (-1)^n . n! . 1^n/ x^(n+1)

Similary

for cos (ax + b); y^n = a^n cos( ax + b + n.π/2)

∴ cos 2x; y^n = 2^n cos (2x + n.π/2)

By Solving above 2 and adding as given we get the above solution.