giving 15 cot A equal to 8 find sin square A + cos square A +tan square A -sec2A
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15cotA =8
cotA =8/15
From this we get that,
opposite side to A =15
Adjacent side to A =8cm
Hypotenuse =17 cm.
now,
sin²A+cos²A+tan²A-sec²A
=(15/17)²+(8/17)²+(15/8)²-(17/8)²
=225+64/289+225-289/64
=289/289-64/64
=1-1
=0
cotA =8/15
From this we get that,
opposite side to A =15
Adjacent side to A =8cm
Hypotenuse =17 cm.
now,
sin²A+cos²A+tan²A-sec²A
=(15/17)²+(8/17)²+(15/8)²-(17/8)²
=225+64/289+225-289/64
=289/289-64/64
=1-1
=0
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