giving reasons find the unknown angle
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this question can be solved by exterior angle property also.
hope it will satisfy you
hope it will satisfy you
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can you solve mine other questions too please
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Let the triangle be ΔABC and m∠A = 70 and m∠B = m∠C = a.
Let D be a point on ray BC such that ∠ACD is exterior angle of ΔABC at point C.
Thus, according to question, m∠ACD = b.
Now, for ΔABC,
m∠A + m∠B + m∠C = 180
∴ 70 + a + a = 180
∴ 70 + 2a = 180
∴ 2a = 180 - 70
∴ 2a = 110
∴ a = 55
We know that measure of an exterior angle is the sum of measures of its interior opposite angles.
In this case ∠ACD is exterior angle and its interior opposite angles are ∠CAB and ∠ABC.
∴ m∠ACD = m∠CAB + m∠ABC
∴ b = 70 + a
∴ b = 70 + 55
∴ b = 125
Thus, a = 55° and b = 125°
Let D be a point on ray BC such that ∠ACD is exterior angle of ΔABC at point C.
Thus, according to question, m∠ACD = b.
Now, for ΔABC,
m∠A + m∠B + m∠C = 180
∴ 70 + a + a = 180
∴ 70 + 2a = 180
∴ 2a = 180 - 70
∴ 2a = 110
∴ a = 55
We know that measure of an exterior angle is the sum of measures of its interior opposite angles.
In this case ∠ACD is exterior angle and its interior opposite angles are ∠CAB and ∠ABC.
∴ m∠ACD = m∠CAB + m∠ABC
∴ b = 70 + a
∴ b = 70 + 55
∴ b = 125
Thus, a = 55° and b = 125°
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