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Answer:
Kapil can do a piece of work in 8 days and Gopal can do the same work in12 days. They start the work together but after 3 days Gopal leaves off . In many days will Kapil do the remaining work
Please tell in inverse and direct methodRaju 1 day work = 1/10
Vicky 1 day work = 1/12
Tinku 1 day work = 1/15
Amount of work done by them(raju+tinku+vicky) in 1 day
= (1/10 + 1/12 + 1/15) = 1/4
Work done by them in 2 day
=2*(1/4) = 1/2
Vicky leaves 3 days before work is completed means remaining 3 day work
is completed by Tinku :
Tinku 3 day work = 3*1/15 = 1/5
Amount of work remaining till now :
= 1 - [(2days work done by them together) + (3 days tinku work)]
= 1-(1/2 + 1/5)
= 3/10
[NOTE : 2DAYS WORK BY THE TOGETHER + 3DAYS TINKU WORK =5DAYS]
[NOTE: NOW WE HAVE TO FINDOUT NUMBEROF DAYS IN WHICH REMAINING WORK IS COMPLETED
BY TINKU AND VICKY]
remaining work = (number of days required) * (tinku + vicky work)
3/10 = X * (1/12 +1/15)
X= 2
TOTAL DAYS = (2days work done by them together) + (3 days tinku work) + (2 days tinku + vicky work)
= 2 + 3 + 2 = 7 ANS