Question

giving u 50 pts pls answer​

Answer 1

$4x {}^{2} + 9y {}^{2} = 36 \\ 9y {}^{2} = 36 - 4x {}^{2} \\ y { }^{2} = \frac{36 - 4x {}^{2} }{9} \\ y = + - \sqrt{ \frac{36 - 4x {}^{2} }{9} } = + - \frac{2}{ \ 3} \sqrt{ {9 - x { }^{2} } } \\ y1 = \frac{2}{3} \sqrt{9 - x {}^{2} } \\ y2 = - \frac{2}{3} \sqrt{9 - x {}^{2} } \\ \frac{dy1}{dx} = \frac{d}{dx} ( \frac{2}{3} (9 - x { {}^{2} }) {}^{1 \div 2} ) = - \frac{2x}{3 \sqrt{9 - x {}^{2} } } \\ \frac{dy2}{dx} = - \frac{dy1}{dx} = \frac{2x}{3 \sqrt{9 - x {}^{2} } }$

hello dude this is your answer

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Answer 2

Step-by-step explanation:

pls mark it as the brainliest answer....