Question

Givn function is [x]^2 - [x^2] which is discontinuous at

Answer 1

Heya!

Here is yr answer.....


=> x² - x²

=> 0


Proof :
~~~~~~

[ a² - b² = (a+b)(a-b) ]

=> (x+x) (x-x)

=> (2x) (0)

=> 0


Hope it hlpz...