Question

glass ball is rubbed with ebonite ball and kept at a distance of 1cm. if force of attraction between them is 10N, find charge on each ball​

Answer 1

Given info : glad ball is rubbed with Ebonite ball and kept at a distance 1cm. force of attraction between them is 10 N.

To find : the charge on each ball is...

solution : let charge on each ball is q.

from Coulomb's force,

F = kq²/r²

here F = 10 N, r = 1cm = 0.01 m , k = 9 × 10^9 Nm²/C²

so, 10 = (9 × 10^9 × q²)/(0.01)²

⇒10 × 10^-4 = 9 × 10^9 × q²

⇒10^-12/9 = q²

⇒q = 10^-6/3 = 0.33 × 10^-6 C = 0.33 μC

Therefore charge on each ball is 0.33μC.

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