Glass has a refractive index of 1.5. a convex lens made of thin glass has a focal length of 20cm in air. it is immersed in water whose refractive index is 4/3. calculate the apparent changed focal length of the lens
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Answer:For the lens in air,
Since, 1fa=(.aug−1)[1R1−1R2]⇒120=(1.5−1)[1R1−1R2]⇒1R1−1R2=110
When the lens is immersed in water,
Since, 1fw=(μgμg−1)[1R1−1R2]⇒1fw=(1.54/3−1)×110
or 1fw=18×110=180 fw=80cm.
Explanation:
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