Question

global insurance company has four salespeople working in hill town. the number of polices sold during the last month is given in matrix​

Answer 1

SOLUTION

TO DETERMINE

Global insurance company has four salespeople working in hill town. the number of polices sold during the last month is given in matrix

EVALUATION

Here the given matrices are

$\displaystyle \sf{A = \begin{pmatrix} 8 & 7 & 6& 8\\ 6 & 9 & 11& 5 \\ 4 & 3 & 2& 0 \\ 0 & 2 & 1& 3\end{pmatrix}}$

$\displaystyle \sf{S = \begin{pmatrix} 1 & 1 & 1& 1\end{pmatrix}}$

ANSWER TO QUESTION : 1

SA

$\displaystyle \sf{= \begin{pmatrix} 1 & 1 & 1& 1\end{pmatrix}}.\begin{pmatrix} 8 & 7 & 6& 8\\ 6 & 9 & 11& 5 \\ 4 & 3 & 2& 0 \\ 0 & 2 & 1& 3\end{pmatrix}$

$\displaystyle \sf{=\begin{pmatrix} 8 + 6 + 4 +0 \: \: & 7 + 9 + 3 + 2 \: \: & 6 + 11 + 2 + 1 \: \: & 8 + 5 + 0 + 3\end{pmatrix} \: }$

$\displaystyle \sf{=\begin{pmatrix} 18 \: \: & 21 \: \: & 20 \: \: & 16\end{pmatrix} \: }$

So the resultant matrix is of order 1 × 4

The elements are 18 , 21 , 20 , 16

ANSWER TO QUESTION : 2

$\sf{A{S }^{t} }$

$\displaystyle \sf{= \begin{pmatrix} 8 & 7 & 6& 8\\ 6 & 9 & 11& 5 \\ 4 & 3 & 2& 0 \\ 0 & 2 & 1& 3\end{pmatrix}.\begin{pmatrix} 1\\ 1 \\ 1 \\ 1\end{pmatrix} }$

$\displaystyle \sf{= \begin{pmatrix} 8 + 7 + 6 + 8\\ 6 + 9 + 11 + 5 \\ 4 + 3 + 2 + 0 \\ 0 + 2 + 1 + 3\end{pmatrix} }$

$\displaystyle \sf{= \begin{pmatrix}29\\ 31 \\ 9 \\ 6\end{pmatrix} }$

So the resultant matrix is of order 4 × 1

The elements are 29 , 31 , 9 , 6

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