Science, asked by deepeshdk, 8 months ago

Glucose is taken in a test tube and acted upon by
hexokinase enzyme. Resulting substrate is
glucose – 6 - phosphate. This isolated metabolic
reaction is considered to be :
(1) In vivo and living
(2) In vivo and non-living
(3) In vitro and living
(4) In vitro and non-living.


please gyus answer ASAP ​

Answers

Answered by arkanil93
4

Answer:

Your answer is (4) In vitro and non-living.

Answered by Anonymous
2

The isolated metabolic reaction is considered to be in vitro and living. (option 3)

  • The process of isolation of organisms or molecules and studying them in a test tube is called in vitro studies.
  • Hexokinase is an enzyme that phosphorylates a glucose molecule to glucose-6-phosphate, initiating glycolysis. Glycolysis the most important process in cellular metabolism.
  • When we add hexokinase to glucose in a test tube and it turns into glucose-6-phosphate, it means that the cell is alive and metabolically active.
  • Hence, the reaction is in vitro and living.
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