Glucose reacts with acetyl chloride to form penta acetyl glucose. It indicates the presence of
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Glucose reacts with acetic anhydride in presence of pyridine
to form penta acetyl derivative. This reaction indicates the
presence of five - OH groups in a molecule of glucose.
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Answer:
The correct answer is 5 OH groups.
Explanation:
Acetylation of glucose:
- When glucose is combined with acetic anhydride, glucose Penta acetate is formed.
- The acetylation of glucose is the name for this process.
- The molecule glucose penta acetate is extremely stable.
- The glucose molecule has 5OH groups.
- When these 5 OH groups react with acetic acid, the acetate group replaces the 5OH groups of glucose.
- As a result, we can conclude that the reaction demonstrates the presence of 5OH groups in the glucose molecule.
- This glucose The beta-D form of glucose is penta acetate. It is water insoluble. Chloroform and methanol are both soluble in it. It has a strong chemical stability and a long shelf life.
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