glucose solution having strength of 18 g/L is isotonic with an aqueous NaCl solution. The strength of NaCl (in g/L) is
Answers
Answered by
9
Answer:
Explanation:
No idea
Answered by
0
Given:
The strength of glucose solution = 18 g/L
This glucose solution is isotonic with aqueous NaCl solution.
To Find:
The strength of an aqueous NaCl solution.
Calculation:
- Moles of glucose = 18/180 = 0.1
⇒ Molarity of glucose = 0.1/1 = 0.1 M
- Isotonic solutions means that the solutions have the same osmotic pressure.
⇒ The osmotic pressure of glucose solution = The osmotic pressure of NaCl solution
⇒ Π (glucose) = Π (NaCl)
⇒ C1 RT = C2 RT
⇒ C2 = 0.1 M
⇒ 1 litre solution contains 0.1 moles of NaCl.
- The mass of 0.1 moles NaCl = 0.1 × 58.5 = 5.85 gm
⇒ The strength of NaCL = 5.85 g/L
Similar questions