Chemistry, asked by shreyansh1845, 8 months ago

glucose solution having strength of 18 g/L is isotonic with an aqueous NaCl solution. The strength of NaCl (in g/L) is​

Answers

Answered by harshverma2691
9

Answer:

Explanation:

No idea

Answered by Jasleen0599
0

Given:

The strength of glucose solution = 18 g/L

This glucose solution is isotonic with aqueous NaCl solution.

To Find:

The strength of an aqueous NaCl solution.

Calculation:

- Moles of glucose = 18/180 = 0.1

⇒ Molarity of glucose = 0.1/1 = 0.1 M

- Isotonic solutions means that the solutions have the same osmotic pressure.

⇒ The osmotic pressure of glucose solution = The osmotic pressure of NaCl solution

⇒ Π (glucose) = Π (NaCl)

⇒ C1 RT = C2 RT

⇒ C2 = 0.1 M

⇒ 1 litre solution contains 0.1 moles of NaCl.

- The mass of 0.1 moles NaCl = 0.1 × 58.5 = 5.85 gm

⇒ The strength of NaCL = 5.85 g/L

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