Question

gmat number series ouestion 42,41,43,40,47,32,56?what is the answer plz give the answer​

Answer 1

Step-by-step explanation:

Given:

$42,41,43,40,47,32,56,?$

To find:

The next number in the series $42,41,43,40,47,32,56,?$  

Solution:

$42,41,43,40,47,32,56,...$

Now separate the given series into odd position alone and even position alone.

Therefore an odd position sequence is,

⇒  $42,43,47,56$

Here the difference between each term goes like this $1^{2} ,2^{2} ,3^{2} .$ .  

⇒ I.e. It goes like follows,

$42+1^{2} =42+1=43\\43+2^{2} =43+4=47\\47+3^{2} =47+6= 56$  

and the even position sequence is,

⇒ $41,40,32$  

Here the difference between each term goes like this $-1^{3} .-2^{3} ,-3^{3} .$.

⇒ I.e. It goes like follows,                

 $41+(-1^3)=41-1=40\\40+(-2^3)=40-8=32$                        

∴ $32+(-3^3)=32-27=5$

Now the sequence is,

 $42,41,43,40,47,32,56,5$  

The sequence goes like this.

Answer:

The next number in the series is  $5.$