Question

Go through the direction given below and
solve the question based on it.
Certain words are coded in a language as
provided below. You need to understand
the basis of coding and answer the
questions asked.
Leap : 4132
Pole : 7143
Lazy: 1256
Year : 5328
What will be the code for Reap in the
language?​

Answer 1

Given :-

Leap : 4132

Pole : 7143

Lazy: 1256

Year : 5328

To Find :-

• code for REAP ?

Solution :-

Comparing first two we get,

→ LEAP : 4132

→ POLE : 7143

Conclusion 1 :- (L, E , P) are common in both. so, code for them will also be common in both , which is (1, 3, 4) . { not in same order.} Also, from first we can conclude that, code for A is fix , which is 2. and from second code for O is fix, which is 7.

Comparing first and third we get,

→ LEAP : 4132

→ LAZY : 1256

conclusion 2 :- common alphabets in both are :- (L and A.) common digits are :- (1 and 2.) from conclusion 1 we have fix code for A . Therefore , Code for L is 1.

Comparing first and fourth we get,

→ LEAP : 4132

→ YEAR : 5328

conclusion 3 :- common alphabets in both are :- (E and A.) common digits are :- (3 and 2.) from conclusion 1 we have fix code for A . Therefore, code for E is 3.

Conclusion 4 :- in second we have :- POLE : 7143 . from conclusion 1st , 2nd and 3rd, we have fix code for O, L and E. Therefore, code for P is 4.

Comparing 3rd and 4th we get,

→ LAZY : 1256

→ YEAR : 5328

Conclusion 5 :- common alphabets = (A , Y) . Digits = (2 , 5) . from first conclusion we already have code for A..Therefore, code for Y is 5. Also, in last now, we have code for Y, E and A. Therefore, code for R is 8.

Therefore, from all conclusions we have :-

• R = 8
• E = 3
• A = 2
• P = 4

Hence, code for REAP is 8324.

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