Question

go Using Euclid's algorithm, find the H.CF of:
1152 11664
1) 1152, 1664
HCF (1152 , 1664) = 128
- 1192
9 12 15 272
1664 = 1152 XL+ 512
-1024
1152, 512 X 2 + 128
128 5)
24
512= 128 X 3.to
-912
HCF = 128
O
i 504, 1188​

Answer 1

Answer:

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Step-by-step explanation:

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