Math, asked by KASHYAP7BOY, 5 months ago

God of mathematics solve it..........

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Answered by Anonymous
5

 \red \bigstar \bold  \answer \\  \\  \frac{ - 1}{ \sqrt{3} } is \: the \: zero \: of \: the \: given \: polunomial \\  \\  \green \bigstar solution \\ p =   \binom{ - 1}{ \sqrt{3}  }  = 3 \binom{ - 1}{ \sqrt{3 {}^{} } }  {}^{2}  - 1 = 3 \binom{1}{3}  - 1 = 0 \\  \frac{1}{ \sqrt{ - 3} } is \: the \: zero \: of \: p(x) = 3 {x}^{2}  - 1 \\ p \binom{2}{ \sqrt{3} }  = 3 \binom{2}{ - 3}  {}^{2}  - 1 = 3 \binom{4}{3}  - 1 = 3 \\ hence \: verified \:  \frac{ - 1}{ \sqrt{3} } is \: the \: zero \: of \: polynomial \: but \\  \frac{2}{ \sqrt{3} } is \: not

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