Question

gogi was driving at 20 m/s he applied break which generated force equal to -500n.find the distance after which the car will stop isf its mass is 100 kg​

Answer 1

Explanation:

There are three forces acting on the rider and bicycle. The weight of the rider and bicycle, W, acts vertically downward from their center of gravity. The normal force, N, of the road acts vertically upward from a point below the center of gravity. And the frictional force, F, of the road acts horizontally to the left.

Answer 2

Answer:

$Velocity of moving vehicle=v0 and decceleration =a</p><p></p><p>Final velocity of the vehicale =0 (As it stops)</p><p></p><p>Let the stopping distance be s</p><p></p><p>Then applying the third equation of motion we have:</p><p></p><p>v2=v02+2(−a)s</p><p></p><p>⇒0=v02−2as</p><p></p><p>⇒s=2av02→ Expression for stopping distance.</p><p></p><p>$

Explanation:

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