Question

gogi was driving at 20 m/s he applied break which generated force equal to -500n.find the distance after which the car will stop isf its mass is 100 kg​

Answer 1

Answer:

40meter

Step-by-step explanation:

F =MA

-500N=100kg×A

A=[-5m/sec²]

V=0[final velocity]

V²=U²+2AS

0=20²+2{-5}{S}

-400  =  -10S

S======40m

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Answer 2

FINAL ANSWER:-

$40\:meters$

GIVEN:-

gogi was driving at $u = 20 m/s$

he applied break (means car will stop after certain time) $v=0m/s$

which generated force equal to $F= -500N$

TO FIND:-

the distance after which the car will stop

FORMULAS USED:-

$F=ma$  [∵F=force , m=mass , a=acceleration]

$v^{2}=u^{2}+2as$ [∵v=final velocity , u=initial velocity , a=acceleration s=distance]

SOLUTION:-

we have given:-

$v=0m/s\\u=20m/s\\F=-500N\\m=100kg$

$F=ma$  ← this is used to find a (acceleration)

$-500=100a$

$a=\frac{-500}{100}$  ⇒ $a=-5m/s$

as we got acceleration so lets put in → $v^{2}=u^{2}+2as$ to get distance covered

$v^{2}=u^{2}+2as$ → $(0)^{2}=(20)^{2}+2*-5*s$

$0=400-10s\\-400=-10s\\s=\frac{-400}{-10}\\s=40 m$

hence car will stop after 40 meters

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