gogi was driving at 20m/s . he applied breakes which generates force equal to -500 netwon find the distance after which the car will stop if its mass is 100 kg.
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F = ma
m = 100kg
F = -500N
On solving we get a = -5m/s^2
Use third equation of motion
v^2 = u^2 + 2as
car stops so v = 0
0 = 20^2 + 2(-5)s
10s = 400
s = 40 m
It will stop after 40m
m = 100kg
F = -500N
On solving we get a = -5m/s^2
Use third equation of motion
v^2 = u^2 + 2as
car stops so v = 0
0 = 20^2 + 2(-5)s
10s = 400
s = 40 m
It will stop after 40m
simerpreetkaur2005:
thank you
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