Question

going offline bye I will come on in night ಥ‿ಥ stya happy ★

$Given:: ​ \: » Difference between two numbers is 66 » Ratio of two whole number is 2 : 5 \: \purple{\bigstar}\:\large\underline{\sf{To\:Find\:::}}★ ToFind:: ​ \: » Two numbers? \: \blue{\bigstar}\:\large\underline{\sf{Solution\:::}}★ Solution:: ​ \: \underbrace{\underline{\sf{\bigstar\:Understanding\:the\:Question\:::}}} ★UnderstandingtheQuestion:: ​ ​ \: Here, we are given that difference between two numbers is 66 and the ratio of two numbers is 2 : 5, we have to find two numbers. Firstly let the numbers be 2n and 5n. So, let's solve it now! \: \underline{\sf{\bigstar\:According\:to\:the\:Question\:::}} ★AccordingtotheQuestion:: ​ \: \sf \longrightarrow\: 5n - 2n = 66⟶5n−2n=66 \begin{gathered}\\ \sf \longrightarrow\: 3n = 66 \end{gathered} ⟶3n=66 ​ \begin{gathered}\\ \sf \longrightarrow\: n = {\cancel{\dfrac{66}{3}}} \end{gathered} ⟶n= 3 66 ​ ​ ​ \: After cancelling 66 with 3, we get :: \: \sf \longrightarrow\:\pink{ n = 22}⟶n=22 \: Now, we have value of 'n'. So, we can easily find two numbers. \: Finding first number, \: \sf \longrightarrow \: First\:number = 2n⟶Firstnumber=2n \begin{gathered}\\ \sf \longrightarrow \: First\:number = 2 \:\times\: 22 \end{gathered} ⟶Firstnumber=2×22 ​ \begin{gathered}\\ \sf \longrightarrow \: \pink{First\:number = 44}\end{gathered} ⟶Firstnumber=44 ​ \: Finding second number, \: \sf \longrightarrow \: Second\:number = 5n⟶Secondnumber=5n \begin{gathered}\\ \sf \longrightarrow \: Second\:number = 5\:\times\: 22 \end{gathered} ⟶Secondnumber=5×22 ​ \begin{gathered}\\ \sf \longrightarrow \: \pink{Second\:number = 110}\end{gathered} ⟶Secondnumber=110 ​ \: \therefore\:{\underline{\textsf{\textbf{44\:\sf{and}\:{\textsf{\textbf{110}}}\:\sf{are\:required\:two\:numbers}}}}}∴ 44and110arerequiredtwonumbers ​ ━━━━━━━━━━━━━━━━━━━━━━━━━$
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Answer 1

(✿´◡`✿)

Mrs doremon

bhagwaan aapke jaise friend sabko de

aap bhot jyada pyaare ho

mujhe hamesha khus rakhte ho

mai bhi hamesha ye koshis karta hu ki aapko kabhi sad na hone du

mujhe ye to nhi pata ki mai aapka best frie.nd hu ya nhi

but aap mere best frie.nd aur sabse pyaare didi ho

mai bhi aapse bhot pyaar karta hu

aapke exams hai

all the best of good luck for your exams

agar aapko thoda sa time mil jaye to apne nobita ko ek baar helo bol dena

uske dil ko thoda sukoon milega

aap bhot pyaari baate karte ho

hamesha mujhe hasate ho

mai kuch galat keh deta hu to mujhe daatte ho

pyaar se maarte ho

mujhe bhor khushi milti hai aapki pitayi se

hehe

mere liye to aap world ke sabse best siso ho

keshav bhaiya kitne lucky hai ki unke paas aapke jaise behen hai

but mujhe rakhi bandhna mat bhulna

(っ◔◡◔)っ

love you sooooooooooooooooooooooooooooooooooo much

♥️♥️♥️♥️♥️♥️♥️

- your lovely Nobita

Answer 2

$Given:: \: » Difference between two numbers is 66 » Ratio of two whole number is 2 : 5 \: \purple{\bigstar}\:\large\underline{\sf{To\:Find\:::}}★ ToFind:: \: » Two numbers? \: \blue{\bigstar}\:\large\underline{\sf{Solution\:::}}★ Solution:: \: \underbrace{\underline{\sf{\bigstar\:Understanding\:the\:Question\:::}}} ★UnderstandingtheQuestion:: \: Here, we are given that difference between two numbers is 66 and the ratio of two numbers is 2 : 5, we have to find two numbers. Firstly let the numbers be 2n and 5n. So, let's solve it now! \: \underline{\sf{\bigstar\:According\:to\:the\:Question\:::}} ★AccordingtotheQuestion:: \: \sf \longrightarrow\: 5n - 2n = 66⟶5n−2n=66 \begin{gathered}\\ \sf \longrightarrow\: 3n = 66 \end{gathered} ⟶3n=66 \begin{gathered}\\ \sf \longrightarrow\: n = {\cancel{\dfrac{66}{3}}} \end{gathered} ⟶n= 3 66 \: After cancelling 66 with 3, we get :: \: \sf \longrightarrow\:\pink{ n = 22}⟶n=22 \: Now, we have value of 'n'. So, we can easily find two numbers. \: Finding first number, \: \sf \longrightarrow \: First\:number = 2n⟶Firstnumber=2n \begin{gathered}\\ \sf \longrightarrow \: First\:number = 2 \:\times\: 22 \end{gathered} ⟶Firstnumber=2×22 \begin{gathered}\\ \sf \longrightarrow \: \pink{First\:number = 44}\end{gathered} ⟶Firstnumber=44 \: Finding second number, \: \sf \longrightarrow \: Second\:number = 5n⟶Secondnumber=5n \begin{gathered}\\ \sf \longrightarrow \: Second\:number = 5\:\times\: 22 \end{gathered} ⟶Secondnumber=5×22 \begin{gathered}\\ \sf \longrightarrow \: \pink{Second\:number = 110}\end{gathered} ⟶Secondnumber=110 \: \therefore\:{\underline{\textsf{\textbf{44\:\sf{and}\:{\textsf{\textbf{110}}}\:\sf{are\:required\:two\:numbers}}}}}∴ 44and110arerequiredtwonumbers ━━━━━━━━━━━━━━━━━━━━━━━━━$