Gold crystallises in ccp structure. The total number of voids present in 197g of gold will be [Au = 197]
(1) 197 N
(2) 2 NA
3) 3 NA
(4) 4 * 197 NA
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Answer:
No of Unit cell in CCP = 4
Voids in octahedral and tetrahedral sites =2n+ n = 3n
Therefore Total voids = 4×3 =12
Hence for 1 atom
12/4 =3 Na
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