Gold has atomic radius 144 pm, crystallises in fcc, the length of unit cell is (a)400 pm. (b)407.3 pm (c)450 pm. (d)300 pm.
Answers
Answered by
0
Answer:
here is the answer
Explanation:
please mark as
Attachments:
Answered by
1
Now, in the question it is given that the atomic radius, r of gold is 144 pm. And the type of cubic cell is FCC. Therefore, let the length of the side of the cell be 'a'. Therefore, the length of the side of the cell is 407.3 pm.
Similar questions