Math, asked by subha123, 1 year ago

Gold is 19 times as heavy as water and copper 9 times as heavy as water. what is the ratio in which these two metals shall be mixed so that the mixture is 15 times as heavy as water?

Answers

Answered by Aviral101
28
Gold = 19x
Copper = 9x.
Gold + copper = 15x.

So from gold it is 4 away.
from copper it is 6 away.

Ratio by reverse=copper:gold
= 4:6 = 2:3.
Answered by parmesanchilliwack
18

Answer:

They are mixed in the ratio of 3:2.

Step-by-step explanation:

Let, quantity g of gold which is 19 times as heavy as water is mixed with quantity c of copper which is 9 times as heavy as water for forming the mixture which is  15 times as heavy as water,

Thus, we can write,

19 of g + 9 of s = 15 ( g + s )

⇒ 19g + 9s = 15g + 15s

⇒ 4g = 6s

\frac{g}{s}=\frac{6}{4}=\frac{3}{2}

Hence, they are mixed in the ratio of 3:2.

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