Question

Gold is 19 times as heavy as water and copper is 9 times as heavy as water. The ratio, in which the two metals should be mixed, so that the mixture is 15 times as heavy as water, is A) 4:3 B) 8:5 C) 3:2 D) 9:5

Answer 1

Step-by-step explanation:

Let the ratio of Gold and copper that taken be a:L

=> 19a + 9L= 15a + 15L

=> 19a - 15a = 15L - 9L

=> 4a = 6 L

=> 4a /6L = 3/2

=> a/L = 3/2

Therefore, Gold and copper are taken in the ratio 3:2

Answer 2

$The \: required \: ratio = 6 : 4$

$= 3 : 2$

Therefore.,

$Option \: \pink { ( C ) } \: is \: correct .$

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