Question

GOLD PACKAGE
A circular disc is rotating about its own axis. An external opposing torque 0.02Nm is applied on the disc
by which it comes to rest in 5 seconds. The initial angular momentum of disc is
a) 0.1 kg m’s-
b) 0.04kgm s-
[ ]
c) 0.025 kgms!
d) 0.01 kgms​

Answer 1

Answer:

Here's your answer

Step-by-step explanation:

C

ˉ

=0.02N/m

t=5sec

torque is applied for 5sec and torque is rate of change of angular momentum so,

angular momentum lost due to decelaration =

C

ˉ

×△t

=(0.02)×5

=0.1

change in angular momentum = final angular momentum − initial angular momentum

0.1=0− Initial angular momentum

∴ Initial angular momentum = 0.1 kg m

2