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Question:
In the above figure,
Angles of ∆ECD are given.
In ∆ABC, ∠BAC = 30°
Find ∠ABC & ∠ACB.
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Answer:
solution is attached above ....
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Step-by-step explanation:
2x + 3x + 4x = 180°
9x = 180°
x = 180/9
= 20
Substitute x value in each of the angles:
CED = 2x
= 40°
ECD = 4x
= 80°
EDC = 3x
= 60°
We know that external angle is equal to sum of two interior opposite angles.
External angle = 80°
angle ABC = 80 - 30 = 50°
ACD + ACB = 180° (Linear Pair)
80 + ACB = 180°
ACB = 180 - 80 = 100°
Hence ABC = 50°
ACB = 100°
Hope it helps:)
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