Question

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Question:
In the above figure,
Angles of ∆ECD are given.
In ∆ABC, ∠BAC = 30°
Find ∠ABC & ∠ACB.​

Answer 1

Answer:

solution is attached above ....

Answer 2

Step-by-step explanation:

2x + 3x + 4x = 180°

9x = 180°

x = 180/9

= 20

Substitute x value in each of the angles:

CED = 2x

= 40°

ECD = 4x

= 80°

EDC = 3x

= 60°

We know that external angle is equal to sum of two interior opposite angles.

External angle = 80°

angle ABC = 80 - 30 = 50°

ACD + ACB = 180° (Linear Pair)

80 + ACB = 180°

ACB = 180 - 80 = 100°

Hence ABC = 50°

ACB = 100°

Hope it helps:)