Question

✨✨Good afternoon brainly vasiyo!!!✨✨

$\huge\underline\mathtt {Question}$
An organic compound containing carbon hydrogen and chlorine has 10% of carbon, 0.84 % of hydrogen and rest chlorine. what is the empirical formula of the compound ​

Answer 1

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➺ Find chorine’s percentage.

Cl= 100- (10.4+0.84)

=100- 11.24

= 88.76%

➺ Find the mass of teach components in grams:

• carbon: 10.4% so 10.4g out of 100g of total mixture.
• hydrogen: 0.84g
• Chlorine: 88.76g

➺ find the no. of moles of each (no. of moles= total mass/ atomic mass):

• Carbon: 10.4/ 12 = 0.8

• hydrogen: 0.84/1 = 0.84
• Chlorine: 88.76/35= 2.5

➺ devide smallest mole vale by all mole values and write their ratio:

$\boxed{ \sf{1:1:3 = C:H:Cl}}$

➺ Write the respective values of ratio as subscrits of the chemical symbol:

C1H1Cl3 = CHCl3

SO CHCL3 IS THE EMPIRICAL FORMULA OF THE COMPOUND.

➺ Find the empirical formula mass:

Mass of C + Mass of H + Mass of 3 atoms of Cl

= empirical formula mass

=12+1+(3x35)

= 118 u

$\huge{ \underline{ \mathfrak{thanks}} { \heartsuit}}$

Answer 2

Explanation:

\huge{ \underline{ \bold{❥ ᴀɴsᴡᴇʀ}}}

❥ᴀɴsᴡᴇʀ

➺ Find chorine’s percentage.

Cl= 100- (10.4+0.84)

=100- 11.24

= 88.76%

➺ Find the mass of teach components in grams:

carbon: 10.4% so 10.4g out of 100g of total mixture.

hydrogen: 0.84g

Chlorine: 88.76g

➺ find the no. of moles of each (no. of moles= total mass/ atomic mass):

Carbon: 10.4/ 12 = 0.8

hydrogen: 0.84/1 = 0.84

Chlorine: 88.76/35= 2.5

➺ devide smallest mole vale by all mole values and write their ratio:

\boxed{ \sf{1:1:3 = C:H:Cl}}

1:1:3=C:H:Cl

➺ Write the respective values of ratio as subscrits of the chemical symbol:

C1H1Cl3 = CHCl3

SO CHCL3 IS THE EMPIRICAL FORMULA OF THE COMPOUND.

➺ Find the empirical formula mass:

Mass of C + Mass of H + Mass of 3 atoms of Cl

= empirical formula mass

=12+1+(3x35)

= 118 u

\huge{ \underline{ \mathfrak{thanks}} { \heartsuit}}

thanks

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