Question

Good afternoon guys

Plz answers!!
Give the right answer or i will repot it ☺️! ​

Answer 1

Answer:

Let DE and DF be the perpendiculars from D on AB and AC respectively.

In △s BDE and CDF, DE=DF (Given)

∠BED=∠CFD=90

∘

BD=DC (∵ D is the mid-point of BC)

∴ △BDE≅△CDF (RHS)

⇒ ∠B=∠C (cpct)

⇒ AC=AB (Sides opp. equal ∠s are equal)

⇒ △ABC is isosceles.

Hope it helps..

stay blessed ✨

hv a great day ahead ❤️

Answer 2

ANSWER

Let DE and DF be the perpendiculars from D on AB and AC respectively.

In △s BDE and CDF, DE=DF (Given)

∠BED=∠CFD=90

∘

BD=DC (∵ D is the mid-point of BC)

∴ △BDE≅△CDF (RHS)

⇒ ∠B=∠C (cpct)

⇒ AC=AB (Sides opp. equal ∠s are equal)

⇒ △ABC is isosceles

1. HOPE IT HELPS.....