Question

Good Afternoon!!!

Question:

Find the oxidation state of the following:

• $\sf{KMnO_{4}}$

• $\sf{K_{2} MnO_{4}}$

• $\sf{{MnO_{4}}^{2-}}$

• $\sf{{MnO_{4}}^{-}}$​

Answer 1

SoluTion:

a). Oxidation state of : $\sf{\red{KMnO_{4}}}$

$\implies$ $\sf{1+x+4(-2)=0}$

$\implies$ $\sf{1+x-8=0}$

$\implies$ $\sf{-7+x=0}$

$\implies$ $\sf{x=+7}$

Hence, oxidation state of $\sf{KMnO_{4}}$ is +7.

$\rule{200}2$

b). Oxidation state of : $\sf{\green{K_{2} MnO_{4}}}$

$\implies$ $\sf{2(1)+x+4(-2)=0}$

$\implies$ $\sf{2+x-8=0}$

$\implies$ $\sf{x-6=0}$

$\implies$ $\sf{x=+6}$

Hence, oxidation state of $\sf{K_{2} MnO_{4}}$ is +6.

$\rule{200}2$

c). Oxidation state of : $\sf{\blue{{MnO_{4}}^{2-}}}$

$\implies$ $\sf{x+4(-2)=-2}$

$\implies$ $\sf{x-8=-2}$

$\implies$ $\sf{x=-2+8}$

$\implies$ $\sf{x=+6}$

Hence, oxidation state of $\sf{{MnO_{4}}^{2-}}$ is +6.

$\rule{200}2$

d). Oxidation state of $\sf{\pink{{MnO_{4}}^{-}}}$

$\implies$ $\sf{x+4(2)=-1}$

$\implies$ $\sf{x-8=-1}$

$\implies$ $\sf{x=-1+8}$

$\implies$ $\sf{x=7}$

Hence, oxidation state of $\sf{{MnO_{4}}^{-}}$ is +7.

Answer 2

Solution:-

a) oxidation state of KMnO4

=> 1 + x + 4(-2) = 0

=> 1 + x -8 = 0

=> x - 7 = 0

=> x = +7

so, oxidation state of KMnO4 is +7

b) oxidation state of K2MnO

=> 2 +x + 4(-2) = 0

=> 2+ x- 8 =0

=> x - 6 = 0

=> x = +6

so, oxidation state of K2MnO4 is +6

c) oxidation state of $\sf{{MnO_{4}}^{2-}}$

=> x + 4 (-2) = -2

=> x - 8 = -2

=> x = -2+8

=> x = +6

so, oxidation state of $\sf{{MnO_{4}}^{2-}}$ is +6

d) oxidation state of $\sf{{MnO_{4}}^{-}}$

=> x + 4(-2) = -1

=> x -8 = -1

=> x = -1 + 8

=> x = +7

so, oxidation state of $\sf{{MnO_{4}}^{-}}$ is +7

________________________