Question

GOOD AFTERNOON ☀☀☀



solve it :

given sec A = 13/12 calculate other trigonomatric ratios?

don't⛔ post irrelevant answers otherwise I reported u​

Answer 1

sec A=13/12 Or H/B=13/12

let H=13K ,B=12K

So in a right angle triangle with angle A

P2 + B2 =H2

P=5k

sin A= P/H = 5/13

Cos A = B/H = 12/13

Tan A = P/B = 5/12

Cosec A= 1/sin A = 13/5

cot A = 1/tan A = 12/5