Question

Good evening guys ❤️❤️

A motorcycle moving with a speed of 5 m/s Is subjected to an acceleration of 0.2 m/s^2 . Calculate the speed of the motorcycle after 10sec and the distance travelled in this time...


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Answer 1

Answer:

Here's your answer

u= 5 m/sec

a= 0.2 m / sec^2

t= 10 sec

By

v= u + at

v= 5 m/sec + 0.2×10

v= 5 + 2

v= 7 m / sec

HERE'S THE SPEED OF THE MOTORCYCLE IS 7 m/sec...

FOR distance...

s= ut+1/2 at^2

s= 50+1/2×0.2 ×100

s = 50+0.1×100

s= 50+10

s= 60

THE DISTANCE IS 60 m..

Hope it helps ✌....

Answer 2

Heya!

Refer the attachment..

Hope it helps you..