good evening guys....
please solve question 8 ,,,step by step...
it's too urgent..
no spams please..
Attachments:
Answers
Answered by
5
Hey buddy❗❗
given==> <APB = 40°
..AP and PB are two tangents respectively..,, since ,, Tangent is _|_ to the radius of the circle..
hence 0A _|_ PA and OB _|_ PB...
hence, <OAP = <0BP = 90°
In quadrilateral PAOB,
<PAO + <PBO + <APB +<AOB = 360°
90° + 90° + <AOB + 40° = 360°
<AOB = 360° - 220°
<AOB = 140°
,,,
since we know that angle subtended at the center of circle..is double that of the angle subtend at the other end of circle....
hence...<AQB= 1/2<AOB...
HENCE,, <AQB = 1/2× 140°
<AQB = 70°.....
hope it helps.....
#####@brainly
given==> <APB = 40°
..AP and PB are two tangents respectively..,, since ,, Tangent is _|_ to the radius of the circle..
hence 0A _|_ PA and OB _|_ PB...
hence, <OAP = <0BP = 90°
In quadrilateral PAOB,
<PAO + <PBO + <APB +<AOB = 360°
90° + 90° + <AOB + 40° = 360°
<AOB = 360° - 220°
<AOB = 140°
,,,
since we know that angle subtended at the center of circle..is double that of the angle subtend at the other end of circle....
hence...<AQB= 1/2<AOB...
HENCE,, <AQB = 1/2× 140°
<AQB = 70°.....
hope it helps.....
#####@brainly
Similar questions