Question

Good evening....guys...
plzzz solve this​

Answer 1

Answer:

$3 {x}^{2} + 4x + 2$

$\alpha + \beta = \frac{ - 4}{3}$

$\alpha \times \beta = \frac{2}{3}$

$\alpha { \beta }^{2} + \beta { \alpha }^{2} = \alpha \beta ( \alpha + \beta )$

$\alpha { \beta }^{2} + \beta { \alpha }^{2} = ( \frac{2}{3} )( \frac{ - 4}{3})$

$\alpha { \beta }^{2} + \beta { \alpha }^{2} = \frac{ - 8}{3}$

Answer 2

take alphabeeta outside as it is common from both term

then u will get

alphabeeta(alpha + beeta)

alphabeeta = c/a = 2/3

alpha + beeta = -b/a = -4/3

2/3 (-4/3)

2/3 × -4/3

= -8/9