Question

Good evening,

Here is Kat ,

At what rate percent per annum will rupees 4000 to rupees 4410 in 2 years when compounded annually.​

Answer 1

a=p(1+r/100)^n

4410=4000(1+r/100)^2

4410/4000=(1+r/100)^2

zero will be cancelled

441/400=(1+r/100)^2

441is the square of21 and 400 is of 20

(21/20)^2=(1+r/100)^2

on equating the powers

21/20=1+r/100

21/20-1= r/100

1/20=r/100

r=5%

Answer 2

Answer:

5%

Step-by-step explanation:

Principal  P = Rs.4000

Time(t) = 2 years

Amount A = Rs. 4410

Rate of interest = ?

No. of compound per year n = 1

Formula of Amount of compound interest :

A=P(1+\frac{r}{n})^{nt}A=P(1+nr)nt

where r is in decimals

Substitute the values

4410=4000(1+r)2

\frac{4410}{4000}=(1+r)^{2}40004410=(1+r)2

\sqrt{1.1025}=(1+r)1.1025=(1+r)

1.05=(1+r)1.05=(1+r)

0.05=r0.05=r

So, rate of interest = 0.05*100= 5%