Question

Good evening
Please help
an object is thrown vertically upwards with an initial velocity of 60 metre per second. calculate height attained by an object , time taken to reach the topmost point ,the velocity of the object when it is halfway up.​

Answer 1

Explanation:

Here, we have to use equation of motion

Here, we taken upward direction as +ve y axis

s : distance travelled

u : initial velocity

t : time

s=ut−

2

1

gt

2

s=60×7−

2

1

×10×7

2

=420−245=175 m