Question

Good evening too all,

Can you please explain to me once how-to factories an algebraic equation? And I have a doubt that how to simplify [a^2-b^2] [a^2+b^2]-[a^2-b^2]^2

Regards
it's a request...

Answer 1

Answer:

Factorization of an algebraic expression is the reverse of multiplication.

-2a²b²

Step-by-step explanation:

Now if we want to Factorise: 64x⁴+2

we will do the multiplication steps in reverse manner like this:

First we take the common. Here the common thing in both these terms is 2 And then we multiply all other things with the common, so that when we open the bracket, the product will be same as the previous.

64x⁴+2 = 2 (32x⁴ +1)

Now if we want to simplify 2(32x⁴+1)

we will do like this: 2*32x⁴ + 2*1 = 64x⁴+2 (we got the same thing again!)

Here is your doubt's simplification:

(a²-b²)(a²+b²) - (a²-b²)

= (a²)² - (b²)² - (a²-b²)   [by using identity: (a+b)(a-b)=a²-b²]

= a⁴-b⁴ - (a²)² - (2*a²*b²) + (b²)²   [identity: (a-b)²=a²-2ab+b²]

=a⁴-b⁴ - a⁴-2a²b²+b⁴

= -2a²b²

pls mark me brainliest!!