Good friends ❤️❤️ but iss question ke baad hehe
The perimeter of a rhombus is 60 cm. the longer diagonal measure 24cm , the length of the shorter diagonal is..
a) 20
b) 18
c) 15
d) 9
plz tell me right answer
Answers
The perimeter of a rhombus is 60 cm. If the length of its longer diagonal measures 24 cm.
As we know that formula of the perimeter of rhombus;
Therefore,the all side of rhombus will be 15 cm .
Now, attachment a figure, a/c question:
In ΔOCB :
AC = 24 cm
OC = 1/2 AC
OC = 1/2 × 24
OC = 12 cm
Using by Pythagoras Theorem :
→ (Hypotenuse)² = (Base)² + (perpendicular)²
→ (BC)² = (OC)² + (OB)²
→ (15)² = (12)² + (OB)²
→ 225 = 144 + 0B²
→ OB² = 225 - 144
→ OB² = 81
→ OB = √81
→ OB = 9 cm
&
BD = 2 × OB
BD = 2 × 9
BD = 18 cm
Thus,
The shorter diagonal will be 18 cm .
\underline{\bf{Given\::}}
Given:
The perimeter of a rhombus is 60 cm. If the length of its longer diagonal measures 24 cm.
\underline{\bf{Explanation\::}}
Explanation:
As we know that formula of the perimeter of rhombus;
\box{\bf{Perimeter = 4 \times side}}
Perimeter=4×side
\mapsto\tt{Perimeter\:of\:rhombus = 4 \times side}↦Perimeterofrhombus=4×side
\mapsto\tt{60 = 4 \times side}↦60=4×side
\mapsto\tt{Side = \cancel{60/4}}↦Side=
60/4
\mapsto\tt{Side = 15\:cm}↦Side=15cm
Therefore,the all side of rhombus will be 15 cm .
Now, attachment a figure, a/c question:
In ΔOCB :
AC = 24 cm
OC = 1/2 AC
OC = 1/2 × 24
OC = 12 cm
Using by Pythagoras Theorem :
→ (Hypotenuse)² = (Base)² + (perpendicular)²
→ (BC)² = (OC)² + (OB)²
→ (15)² = (12)² + (OB)²
→ 225 = 144 + 0B²
→ OB² = 225 - 144
→ OB² = 81
→ OB = √81
→ OB = 9 cm
&
BD = 2 × OB
BD = 2 × 9
BD = 18 cm
Thus,
The shorter diagonal will be 18 cm .
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