Question

Good morning
50 points.
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A heavy uniform chain partly lies on a horizontal table. If the coefficient of friction between the chain and the
table surface is 0.25, then the maximum fraction of the length of the chain that can hang over edge of the table
(A) 20%
(B) 25%
(C) 33%
(D) 15%
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plz answer with full explanation ​

Answer 1

Answer:

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Answer 2

Answer :

Option => A

20% of total length can hang over the edge.

Explanation :

Given :

◆ Coefficient of friction = 0.25

★ Consider the -

◆ Total length of chain be as - L

◆ The length which is hang over as - l

◆ Remaining part which will be on table as - ( L - l )

We know that :

Tension :

Mg (of hanging part).

{ Here, We have to use Free Body Diagram }

⇒ T = mg than m = $\sf \dfrac{T}{g}$

⇒ F = uR

As we know, Linear mass desity = $\sf \dfrac{dm}{l}$

Remember -

Hanging part :

M = (λ) lamda l.

Remaining one as - m = (λ)lamda [L-l]

Substitute the value in equation of equilibrium :

Friction force on [L-l] length should be = to tension.

{ l is cancelled here }

$\implies \sf \dfrac{l}{L} = \dfrac{1}{5}\\ \\ \\\implies \sf \dfrac{l}{L} \times 100 = 20\%$

∴ Option => A (20%) is correct.