good morning everyone. ☺
give answer of both questions.
Attachments:
Answers
Answered by
2
hey here is your answer...
Attachments:
aaryan90:
thanks
Answered by
2
HEY MATE......
HERE IS THE ANSWER.......
_______________________________________
5)
If 6n end with the digit 0, then it must have 2 and 5 as a common factor. But, we know that, the prime factors of 6n are 2 and 3.
Therefore, 6n can never end with the digit 0.
--------------------------------------------------------------------------
6)
i)
Given, 7×11×13+13
Now,
7×11×13+13
=13(7×11+1)
=13(77+1)
=13×78
=1014
Here, 1014 is a composite number which can be expressed as the product of primes.
therefore, it is a composite number.
ii)
Given, 7×6×5×4×3×2×1+5
Now,
7×6×5×4×3×2×1+5
=5(7×6×1×4×3×2×1+1)
=5(1008+1)
=5×1009
=5045
Here, 5045 is a composite number which can be expressed as the product of primes.
Therefore, it is a composite number.
________________________________________
~~HOPE IT WILL HELP YOU~~
❤️please mark the answer as the brainliest one❤️
~~~~~~~~~THANK YOU~~~~~~
HERE IS THE ANSWER.......
_______________________________________
5)
If 6n end with the digit 0, then it must have 2 and 5 as a common factor. But, we know that, the prime factors of 6n are 2 and 3.
Therefore, 6n can never end with the digit 0.
--------------------------------------------------------------------------
6)
i)
Given, 7×11×13+13
Now,
7×11×13+13
=13(7×11+1)
=13(77+1)
=13×78
=1014
Here, 1014 is a composite number which can be expressed as the product of primes.
therefore, it is a composite number.
ii)
Given, 7×6×5×4×3×2×1+5
Now,
7×6×5×4×3×2×1+5
=5(7×6×1×4×3×2×1+1)
=5(1008+1)
=5×1009
=5045
Here, 5045 is a composite number which can be expressed as the product of primes.
Therefore, it is a composite number.
________________________________________
~~HOPE IT WILL HELP YOU~~
❤️please mark the answer as the brainliest one❤️
~~~~~~~~~THANK YOU~~~~~~
Similar questions