Good morning everyone start your morning by solving the question in the attachment
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Given, Diameter of road roller = 0.7 m
Then, radius of road roller = 0.35 cm.
Given, Width of road roller h = 1.2 m.
We know that curved surface area of road roller = 2πrh
⇒ 2 * (22/7) * (0.35) * 1.2
⇒ 2 * 22 * 0.05 * 1.2
⇒ 2.64 m^2
Given , Area of playground = 120 * 44.
Length = 120 m.
Breadth = 44 m.
We know that Area = length * breadth
= 120 * 44
= 5280 m^2.
Hence,
Total number of revolutions = Area of field/Curved surface area of roller
= 5280/2.64
= 2000.
Therefore, total number of revolutions = 2000.
Hope this helps!
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