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Two ships leave a port at the same instant. One sails at 30km/hr in the direction N 32° E while the other sails at 20 km/hr in the direction S 58° E. After two hours the ships are distant from each other by.
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Let two ships started from point O at the speed of 30 km/hr and 20 km/hr respectively, after two hours they reach at points A and B.
Now, ∠NOA = 32° and ∠SOB = 58° ,
Then, ∠AOB = 180° - (32° + 58°) = 90°
Since ΔAOB is a right triangle in which OA = 2 x 30 = 60 km and OB = 2 x 20 = 40 km
Since, AB = √OA2 + OB2
= √(60)2 + (40)2
= √5200
= 20√13
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