good morning frnds...plzz ans fast ...ans plz plz plz don't give Irrelevant answers ........otherwise their answers would be reported ...i'm not jokin'
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hey mate how are you ?
we all know that the sum of opposite angles of quadrilateral is equals to 180 degree so in the figure angle b is given as 50 degree so angle bd+ angle b is equals to 180 degree from this equation we can find angle b angle b is equals to 130 degree..
we do the same thing angle c + angle is equal to 180 degree the answer will come 110 degree
now you are the bisector of angle A and b from this angle is equals to 130 /2
angle OAB = 65 °
and angle OBA = 110/2 = 55°
now in triangle AOB
by angle sum property ...
angle OAB + angle OBA + angle AOB = 180°
65° + 55° + x = 180°
120 + x = 180
so x = 60° (answer )
I hope this will help you please mark as brainliest
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answer for the given problem is given
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