good morning guys please help me
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PROCEED AS UNDER :
8/(x+3) - 2/(2-x) = 2
=> 8(2-x)-2(x+3) = 2(x+3)(2-x)
=> 16-8x-2x-6 = (2x+6) (2-x)
=> 10-10x = 4x-2x²+12-6x
=> 10-12-10x-4x+6x+2x² = 0
=> 2x²-2-8x = 0
=> 2(x²-1-4x) = 0
=> x²-1-4x = 0/2 = 0
=> x²-4x = 0+1 = 1
=> x²-4x+4 = 1+4 [Adding 4 on both sides]
=> (x-2)² = 5
=> √(x-2)² = √5 [Taking square root on both sides]
=> x-2 = √5
=> x = √5+2
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