Question

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Qu: A two digit number is such that the product of its digit is 18. When 63 is subtracted from the number the Digits interchange their places. Find the number.
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Answer 1

$\huge \bf{ \underline{ \overline{ \mid{ \red{Answer - }} \mid}}}$

$\underline{ \underline{ \bold{GIVEN - }}}$Product of the digit =18

$\underline{ \underline{ \bold{TO \: FIND - }}}$The number

Now, let the tens and units digit of the required number be $x \: and \: y$Respectively. Then,

$xy = 18 \implies \: y = \frac{18}{x} \: \: \: ....(1)$

And, $(10x + y) - 63 = 10y + x \: \: \: \: ..........(2)$

Putting $y= \frac{18}{x}$From (1) into (2),we get

$x - \frac{18}{x} = 7 \\ \implies \: {x}^{2} - 18 = 7x \\ \implies \: {x}^{2} - 7x - 18 = 0 \\ \implies \: {x}^{2} - 9x + 2x - 18 = 0 \\ \implies \: x(x - 9) + 2(x - 9) = 0 \\ \implies \: x - 9 = 0 \: or \: x = - 2 \\ \implies \: x = 9$[tex]

Putting x =9 in (1),we get y=2.

Thus, the tens digit is 9 and the unit digit is 2.

Hence the required number is 92.

Answer 2

Answer:

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Step-by-step explanation:

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