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if mass of a car is 1500 kg then how much amount of work has to be done to increase its speed from 30km /h to 60km/h
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Work = Change in kinetic energy
= 0.5 m (v² - u²)
= 0.5 × 1500 kg × [(60 × 5/18 m/s)² - (30 × 5/18 m/s)²]
= 156250 joules
= 156.25 kJ
Answered by
0
Mass of the car,m= 1500kg
Initial velocity of the car = 30km/hr
= 30×1000m/60 ×60s
=8.33m/s
Similarly,the final velocity of the car,
v= 60km/hr
=16.67 m/s
Therefore,the initial kinetic energy of the car,
E(initial) = 1/2 mu^2
=1/2×1500×8.33
52041.68 J.
The final kinetic energy of the car,
E(final) = 1/2 1500×16.67
=208416.68 J.
Thus, the work done = change in kinetic energy
= E(final) - E(initial)
= 208416.68 - 52041.68
= 156375 J.
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