Physics, asked by brainlist6, 1 year ago

good morning

if mass of a car is 1500 kg then how much amount of work has to be done to increase its speed from 30km /h to 60km/h


with explanation ♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️✏✏♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️✏✏

Answers

Answered by samyak170195
1

Work = Change in kinetic energy

= 0.5 m (v² - u²)

= 0.5 × 1500 kg × [(60 × 5/18 m/s)² - (30 × 5/18 m/s)²]

= 156250 joules

= 156.25 kJ

Answered by sonabrainly
0

Mass of the car,m= 1500kg

Initial velocity of the car = 30km/hr

= 30×1000m/60 ×60s

=8.33m/s

Similarly,the final velocity of the car,

v= 60km/hr

=16.67 m/s

Therefore,the initial kinetic energy of the car,

E(initial) = 1/2 mu^2

=1/2×1500×8.33

52041.68 J.

The final kinetic energy of the car,

E(final) = 1/2 1500×16.67

=208416.68 J.

Thus, the work done = change in kinetic energy

= E(final) - E(initial)

= 208416.68 - 52041.68

= 156375 J.


sonabrainly: mark it the brainliest
brainlist6: 1000 khase aaya
Similar questions