Good morning mates ? 17. An altitude of a triangle is five-thirds the length of its corresponding base. If the altitude be
same. Find the base and the altitude of the triangle.
Answers
Step-by-step explanation:
The base and altitude of the triangle is 12 cm and 20 cm respectively. We are given that An altitude of the triangle is five third the length of its corresponding base. Hence the base and altitude of the triangle is 12 cm and 20 cm respectively..
Answer:
Let the length of corresponding base be
Let the length of corresponding base be x
Let the length of corresponding base be xx
Let the length of corresponding base be xx.
Let the length of corresponding base be xx.Thus, altitude will be
Let the length of corresponding base be xx.Thus, altitude will be 5
Let the length of corresponding base be xx.Thus, altitude will be 53
Let the length of corresponding base be xx.Thus, altitude will be 53x
Let the length of corresponding base be xx.Thus, altitude will be 53x53x
Let the length of corresponding base be xx.Thus, altitude will be 53x53x.
Let the length of corresponding base be xx.Thus, altitude will be 53x53x.Now, it is given that altitude is increased by
Let the length of corresponding base be xx.Thus, altitude will be 53x53x.Now, it is given that altitude is increased by4
Let the length of corresponding base be xx.Thus, altitude will be 53x53x.Now, it is given that altitude is increased by44
Let the length of corresponding base be xx.Thus, altitude will be 53x53x.Now, it is given that altitude is increased by44cm i.e.,
53x+4
3x+453x+4
3x+453x+4and base is decreased by
3x+453x+4and base is decreased by2
3x+453x+4and base is decreased by22
3x+453x+4and base is decreased by22cm i.e.,
3x+453x+4and base is decreased by22cm i.e.,x
3x+453x+4and base is decreased by22cm i.e.,x−
3x+453x+4and base is decreased by22cm i.e.,x−2
3x+453x+4and base is decreased by22cm i.e.,x−2x−2
3x+453x+4and base is decreased by22cm i.e.,x−2x−2.
3x+453x+4and base is decreased by22cm i.e.,x−2x−2.The area is same for both.
3x+453x+4and base is decreased by22cm i.e.,x−2x−2.The area is same for both.Therefore,
3x+453x+4and base is decreased by22cm i.e.,x−2x−2.The area is same for both.Therefore,12×x×53x
3x+453x+4and base is decreased by22cm i.e.,x−2x−2.The area is same for both.Therefore,12×x×53x=
3x+453x+4and base is decreased by22cm i.e.,x−2x−2.The area is same for both.Therefore,12×x×53x=12×(53x+4)×(x−2)