Math, asked by priyaagarwal11, 1 year ago

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The angle of elevation of a jet plane from a point A on the ground is 60°. After a flight of 15seconds, the angle of elevation changes to 30°. If the jet plane is flying at a constant height of 1500√3 metres, find the speed of jet plane (√3=1.732).
If you answer I will surely mark you as brainliest.


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Answers

Answered by ujjwalusri
3
Draw diagram based on gives conditions. mark E , D,C  points down and A,B points up.)

Tan 60 = AD/ED

√3 = 1500√3/ED

ED = 1500

Tan 30 = BC/EC


1/√3 = 1500√3/EC

DE = EC - ED

4500-1500

= 3000

PLANE TRAVELS 3000 m  in 15 sec.

Speed = Dstance/Time

= 3000/15

200 m/s.

Jet plane speed = 200m/s.

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Answered by ganikaku2
1
this is for u my friend
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