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The angle of elevation of a jet plane from a point A on the ground is 60°. After a flight of 15seconds, the angle of elevation changes to 30°. If the jet plane is flying at a constant height of 1500√3 metres, find the speed of jet plane (√3=1.732).
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kanish29:
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Draw diagram based on gives conditions. mark E , D,C points down and A,B points up.)
Tan 60 = AD/ED
√3 = 1500√3/ED
ED = 1500
Tan 30 = BC/EC
1/√3 = 1500√3/EC
DE = EC - ED
4500-1500
= 3000
PLANE TRAVELS 3000 m in 15 sec.
Speed = Dstance/Time
= 3000/15
200 m/s.
Jet plane speed = 200m/s.
Tan 60 = AD/ED
√3 = 1500√3/ED
ED = 1500
Tan 30 = BC/EC
1/√3 = 1500√3/EC
DE = EC - ED
4500-1500
= 3000
PLANE TRAVELS 3000 m in 15 sec.
Speed = Dstance/Time
= 3000/15
200 m/s.
Jet plane speed = 200m/s.
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