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Answer 1

Step-by-step explanation:

b.

Area of rhombus = 35 m², altitude = 7 m.

Let the side be a.

Area of rhombus = Base * altitude

=> 35 = a × 7

=> a = 35/7

=> a = 5

Thus, Side of rhombus = 5 m

Now,

Perimeter of rhombus = 4 × side

= 4 × 5

= 20 m

Therefore, perimeter = 20 m.

c.

Area = 48 cm², base = 12 cm.

Area of triangle = ½ *  base * altitude

Then,

altitude = 2 * area/base

           = 2 *  48/12

           = 8 cm

Therefore, Altitude = 8 cm.

Hope it helps!

Answer 2

Answer:

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B.Given:-

$Area\:of\:a\:rhombus\:is\:35{m}^{2}$

$Altitude\:is\:7\:m$

To find out:-

★Perimeter of rhombus

Solution:-

Let's consider the base of a rhombus be X m.

We know that,

Area of a rhombus = Base × Altitude

$\implies$35 = Base × 7

$\implies$Base = 35/7 m

$\implies$Base = 5 m.

Then,

★Perimeter of rhombus = 4 × side/base

Perimeter = 4 × 5 m

★ Perimeter = 20 m

C•Given:-

$Area\:of\:a\:triangle=48{cm}^{2}$

$Base=12\:cm$

To find out:-

★ Altitude of the triangle

Solution:-

We know that,

Area of a triangle= 1/2 × base × altitude

$\implies$48 = 1/2 × 12 × altitude

$\implies$48 = 6 × altitude

$\implies$Altitude = 48/6 cm

$\implies$Altitude = 8 cm

★ Altitude = 8 cm

Hope it helps you ♡ ♡ ♡